Rotational motion

Building a Concept Map of Motion

Basic Concepts

Rotational Motion Analogs

Momentum

Impulse

Work and Energy

Key Relationships and Insights

Examples

Applying a force to a skating object over time changes its momentum, which is a measure of its tendency to keep moving [26].

Exerting a torque on a seesaw over time changes its angular momentum, affecting its rotational motion [18].

The connection between rotational work and translational work

Imagine a mass at the end of a long, massless pole. You are trying to push the mass forward by applying a torque to the opposite end of the pole. in an infinitesimal slice of time, the mass will move a tiny distance forward in a straight path. Therefore, the work done on the mass in that instant is equal to the force applied to it by its end of the lever, times the distance it moved. The force applied at the mass end is scaled down by the length of the lever arm though, due to mechanical advantage.

However, its distance of motion is scaled up by exactly the same factor for the same reason. For small angles, sin(x) = x. Since the distance traveled at the end of the lever arm is rsin(α), defining a torque as fd and then applying it over angle α gives you fdsin(α). Then you get the equation work=fdsin(α) but fd is torque, and α=sin(α) for tiny angles, so it becomes work=τα.

Springs

Springs are elastic, meaning that they can be stretched and will then return to their original shape. The more you deform them, the harder they resist. This leads to Hooke's Law, which says that the restoring force of a spring is proportional to the distance it's been deformed: F=kd. k is the spring constant, which is a number that basically says "for every distance you stretch the spring, it will be this much harder to keep going." The unit of k is Nm, which makes sense (newtons per meter), but it simplifies to the weird unit kgs2, which is very non-intuitive.

Springs have an elastic limit, which is the point where they can't recover from being deformed any farther. If you moosh a spring past its elastic limit, you will leave a permanent change in it. As long as you stay within the elastic limit, the spring can last essentially forever, barring the effects of other parts of the real world (like corrosion and metal impurities).

Bobbing on a spring

If you put a weight on the end of a spring and then give it a bump so that it bounces up and down, it will keep bouncing back and forth for quite a while (in a perfectly elastic spring without friction, it would go forever). This is a visual demonstration of conversion back and forth between kinetic energy and elastic potential energy. The kinetic energy of the weight is enough to pull the spring past its neutral point, but the force increases and the weight does work to stretch the spring. That work is stored as elastic potential energy in the spring, and once all of the kinetic energy is spent, that potential energy gets released as the spring returns toward neutral and accelerates the weight in the other direction. However, by the time it gets to neutral again, the weight is going at its top speed, so the cycle just has to repeat in the other direction, and it keeps going until friction kills it.

So, what happens with momentum in that situation? Clearly the mass gains momentum as it moves, and the momentum must be transferred somewhere because it's conserved. Where does it come from and where does it go? The answer is simply that it comes from whatever the spring is attached to, and it goes right back there. Imagine that one end of the spring is attached to a massive cannon ball, and the other is attached to a little steel marble. The whole contraption is floating in space. Now you pull the marble to get it moving back and forth. You'll see the marble move much farther than the cannon ball, but both of them will be moving in response to the force from the spring. The cannon ball is moving so slowly and such a small amount that its kinetic energy is barely changing (remember kinetic energy equals the force times the distance moved, which is basically zero here), but its momentum will exactly match the marble's.